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Report prepared for Guillaume Thibodeau-Fortin (Stove Builder International Inc.) on
6/26/2019 7:45:42 AM
TEST REPORT 103536746MTL-002
TEST REPORT FOR STOVE BUILDER INTERNATIONAL INC.
Report No.: 103536746MTL-002
Date: 07/13/18
MU OF c
E
AND MU
T
Thus the result in this example would be:
ET = 13.00g ± 0.44 g at a 95% confidence level.
EFFICIENCY – CSA B415.1
The change in enthalpy of the circulating air shall be calculated using the moisture content and
temperature rise of the circulating air, as follows:
Where:
Δh
Δt
1.006 = specific heat of air, kJ/kg °C
1.84
x
The equivalent duct diameter shall be calculated as follows:
Where:
ED
H
Version: 05/10/17
Stove Builder International Inc. | 44826 | Rev: May 31 2019 2:49PM | Uncontrolled Copy
r
c
= BG
/(QBG x θ) = 0.002/(0.15 x 180) = 0.000074
r
c
δc
/δBG
= 1/Q
• Θ = 1/0.15 • 180 = 0.03704
r
c
BG
2
δc
/δQ
= -BG
/Q
• Θ = -0.002/0.15
r
BG
c
BG
2
δc
/δΘ = -BG
/Q
• Θ
= -0.002/0.15 • 180
r
c
BG
MUc
= √(0.00027 • 0.03704)
r
√ + (0.1 • - 0.0000004)
Thus, c
would be 0.074 mg/dscf ± 0.01 mg/dscf at 95% confidence level.
r
ET
E
= (c
– c
) Q
θ = (0.000555 - 0.000074) x 150 x 180 = 13.00g
T
s
r
sd
δE
/δc
= Q
• Θ = 150 • 180 = 27,000
T
s
std
δE
/δc
= Q
• Θ = 150 • 180 = 27,000
T
r
std
δE
/δQ
= c
• Θ – c
• Θ = 0.000555 • 180 – 0.000074 • 180 = 0.08667
T
std
s
r
δE
/δΘ = c
• Q
– c
• Q
T
s
std
r
std
MU
= √(27,000 • 0.0000081)
ET
2
√ + (0.07222 • 0.1)
Δh = Δt (1.006 + 1.84x)
= change in enthalpy, kJ/kg
= temperature rise, °C
= specific heat of water vapor, kJ/kg °C
= humidity ratio, kg/kg
ED = 2HW/H+W
= equivalent duct diameter
= duct height, m
(14 OF 21)
2
• 180 = -0.0004938
2
= -0.0000004
2
2
+ (0.0015 • - 0.0004938)
2
= 0.00001g
= 0.000555 • 180 – 0.000074 • 180 = 0.07222
2
2
+ (27,000 • 0.00001)
(0.08667 • 3)
= 0.436
Page 14 of 21
8431 Murphy Drive
Middleton, WI 53562
Telephone: 608-836-4400
Facsimile: 608-831-9279
www.intertek.com/building
2
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