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223 008
In the above setup schematic, the course difference is expressed as δ=d
d
and d
2
Express the squares of these hypotenuses:
2
d
=
2
2
d
=
1
Write the difference:
2
d
2
verify that:
The computerised study of the denominator Φ(θ) of δ by mans of ACTILAB yields its
variations in the experimental conditions.
Plot the representative curve of Φ(θ) versus θ:
(θ varies at most from -60° to +60° (-π/3 to +π/3))
φ(θ)
Calculate the relative difference (Φ(θ)-2D)/2D for the various positions:
What conclusion can you make?
What is the approximate expression of the course difference:
What is the expression of δ for the peaks? ( with λ=0.84 cm).
Since
ENGLISH
Calculation of the course difference
are the hypotenuses of two rectangular triangles (MhS
1
2
- d
=(d
-d
)(d
+d
)=
1
2
1
2
1
δ
=
2
a
+
2
D
4
Approximations
−π/3
−π/6
D=
θ=0
:
θ=+π/6 or -π/6 :
θ=+π/3 or -π/3 :
Calculation of the number of peaks
λ
is constant, what can be said about
a
θ
2
aD
sin(
)
a
θ
+
+
+
2
aD
sin(
)
D
4
0
+π/6
cm ; a=
cm
θ
sin(
)
?
62
-d
2
1.
and MhS
).
1
2
2
θ
−
aD
sin(
)
θ
+π/3
δ
≈
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