LG MULTI V ARUB Série Manuel D'utilisation page 35

N The Amount of Refrigerant
The calculation of the additional charge should take account of the length of pipe.
Product charge(1unit)(kg(lbs))
A
B
Additional charge (kg(lbs))
=
Total liquid pipe (m(ft)): Ø22.2mm(7/8inch)
+
Total liquid pipe (m(ft)): Ø19.05mm(3/4inch)
+
Total liquid pipe (m(ft)): Ø15.88mm(5/8inch)
+
Total liquid pipe (m(ft)): Ø12.7mm(1/2inch)
+
Total liquid pipe (m(ft)): Ø9.52mm(3/8inch)
+
Total liquid pipe (m(ft)): Ø6.35mm(1/4inch)
+
Number of installed HR units
+
CF(kg(lbs)) (Correction factor)
Total amount(kg(lbs))
CAUTION If a negative result is obtained from
the calculation, no refrigerant needs
to be added.
HP(Ton)
Product Charge(kg(lbs))
CF(kg(lbs))
WARNING
Regulation for refrigerant leakage
: the amount of refrigerant leakage should satisfy the following equation for human safety.
Total amount of refrigerant in the system
Volume of the room at which indoor unit of the least capacity is installed
❐ If the above equation can not be satisfied, then follow the following steps.
- Selection of air conditioning system: select one of the next
1. Installation of effective opening part
2. Reconfirmation of outdoor unit capacity and piping length
3. Reduction of the amount of refrigerant
4. Installation of 2 or more security device (alarm for gas leakage)
- Change indoor unit type
: installation position should be over 2m(6.6ft) from the floor (wall mounted type ¡ cassette type)
- Adoption of ventilation system
: choose ordinary ventilation system or building ventilation system
- Limitation in piping work
: Prepare for earthquake and thermal stress
WARNING
Refer to model information since the CF value of correction factor differs depending on model.
Ex) 10HP
x 0.237 lbs/ft
x 0.178 lbs/ft
A: Ø12.7(1/2), 50m(164ft)
B: Ø9.52(3/8), 10m(33ft)
x 0.116 lbs/ft
C: Ø9.52(3/8), 10m(33ft)
D: Ø9.52(3/8),10m(33ft)
x 0.079 lbs/ft
E: Ø6.35(1/4), 10m(33ft)
x 0.041 lbs/ft
x 0.015 lbs/ft
x 1.1 lbs
Additional Charge = A x 0.061 + B x 0.061 + C x 0.061
= +
A B
Additional Charge = A x 0.061 + B x 0.061 + C x 0.061
8(6.5) 10(8.0) 12(9.5)
8 8 8
(17.6) (17.6) (17.6)
-1 0 1
(-2.2) (0) (2.2)
Refrigerant piping installation
Outdoor unit
HR unit (1EA)
Indoor unit
+ (a+b+c+d+e) x 0.022 + CF
= 40 x 0.061 + 20 x 0.061 + 20 x 0.061
+ (10 x 5) x 0.022 + 0.5(HR)+0(CF)
= 6.48(kg)
+(a + b + c + d + e) x 0.022 + CF
= 131 x 0.041 + 65.6 x 0.041 + 65.6 x 0.041
+ (32.8 x 5) x 0.015 +1.1(HR)+0(CF)
= 14.3(lbs)
14 16(12.5) 18(14.5) 20(16.0)
8 8 16
(17.6) (17.6) (35.3)
2 3 -1
(4.4) (6.6) (-2.2)
0.44kg / m
22(17.5) 24(19.0)
16 16 16
(35.3) (35.3) (35.3)
0 1 2
(0) (2.2) (4.4)
3 (0.028(lbs/ft 3 .))
Installation Manual 35