Jeulin Moduson 2 Mode D'emploi page 22

Ultrasounds
®
Moduson 2 transmitter telemeter 12V
Ref : 222 082
3.5 What is the depth of the box?
The front face of a cardboard box was removed and replaced by a facial tissue paper. We
propose to determine the depth I of the box using ultrasound waves.
Top view diagram of the experiment:
Channel 1
Channel 2
Here are the oscillograms obtained:
• Oscillogram 1 corresponds to the transmitter
• Oscillogram 2 corresponds to the receiver
• The horizontal adjustment is 2 ms per division.
1. Observe oscillogram 2 and explain what the first and second receptions correspond to.
2. Determine from this oscillogram the distances d
Check the result using a graduated ruler.
Partial answer:
1. to t
2. d1 =(3400.61)/2 = 104 mm; d2 = (3401.52)/2 = 258 mm; l = 154mm ; 160mm with a
ENGLISH
E
R
d
1
= 0.61 ms corresponds the reception of ultrasound waves reflected by the tissue
1
paper, to t = 1.52 ms corresponds the reception of ultrasound waves transmitted through
2
the tissue paper, then reflected by the bottom of the box.
ruler.
box
d
2
and d , then find the depth l of the box.
1 2
21
l