SBI CAMBRIDGE II Mode D'emploi page 223

Report prepared for Guillaume Thibodeau-Fortin (Stove Builder International Inc.) on
6/17/2019 7:40:40 AM
TEST REPORT 103819589MTL-001
TEST REPORT FOR STOVE BUILDER INTERNATIONAL INC.
Report No.: 103819589MTL-001
Date: 03/26/19
E AND MU
T
Thus the result in this example would be:
ET = 13.00g ± 0.44 g at a 95% confidence level.
EFFICIENCY – CSA B415.1
The change in enthalpy of the circulating air shall be calculated using the moisture content and
temperature rise of the circulating air, as follows:
Where:
Δh
Δt
1.006 = specific heat of air, kJ/kg °C
1.84
x
The equivalent duct diameter shall be calculated as follows:
Where:
ED
H
W
The air flow velocity shall be calculated as follows:
where
V
F
P
C
P
Version: 05/10/17
Stove Builder International Inc. | 48202 | Rev: May 31 2019 10:15AM | Uncontrolled Copy
ET
E = (c – c ) Q θ = (0.000555 - 0.000074) x 150 x 180 = 13.00g
T s r sd
δE /δc = Q • Θ = 150 • 180 = 27,000
T s std
δE /δc = Q • Θ = 150 • 180 = 27,000
T r std
δE /δQ = c • Θ – c • Θ = 0.000555 • 180 – 0.000074 • 180 = 0.08667
T std s r
δE /δΘ = c • Q – c • Q
T s std r std
MU = √(27,000 • 0.0000081)
ET
2
√ + (0.07222 • 0.1)
Δh = Δt (1.006 + 1.84x)
= change in enthalpy, kJ/kg
= temperature rise, °C
= specific heat of water vapor, kJ/kg °C
= humidity ratio, kg/kg
ED = 2HW/H+W
= equivalent duct diameter
= duct height, m
= duct width, m
V = F x C x 34.97 x √T/28.56(P
p p
= velocity, m/s
= Pitot tube calibration factor determined from vane anemometer measurements
= Pitot factor
= 0.99 for a standard Pitot tube or as determined by calibration for a Type S Pitot tube
(14 OF 20)
= 0.000555 • 180 – 0.000074 • 180 = 0.07222
2 2
+ (27,000 • 0.00001) (0.08667 • 3)
= 0.436
+ P )
baro s
Page 14 of 20
1829, 32nd AVenue
Lachine, Quebec, Canada, H8T 3J1
Telephone: (514)631-3100
Facsimile: (514)631-1133
www.intertek.com/building
2
GFT-OP-10c
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